(1/8^(2-2n)=16

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Solution for (1/8^(2-2n)=16 equation: 



(1/8^(2-2n)=16

We move all terms to the left:

(1/8^(2-2n)-(16)=0



Domain of the equation: 8^(2-2n)-16!=0

We move all terms containing n to the left, all other terms to the right

8^(2-2n)!=16

n∈R



We add all the numbers together, and all the variables

(1/8^(-2n+2)-16=0

We multiply all the terms by the denominator


(1=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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